QSensorManager Class

QSensorManager class handles registration and creation of sensor backends. 更多...

头: #include <QSensorManager>
qmake: QT += sensors

静态公共成员

QSensorBackend * createBackend (QSensor * sensor )
bool isBackendRegistered (const QByteArray & type , const QByteArray & identifier )
void registerBackend (const QByteArray & type , const QByteArray & identifier , QSensorBackendFactory * factory )
void setDefaultBackend (const QByteArray & type , const QByteArray & identifier )
void unregisterBackend (const QByteArray & type , const QByteArray & identifier )

详细描述

QSensorManager class handles registration and creation of sensor backends.

Sensor plugins register backends using the registerBackend () 函数。

QSensor::connectToBackend () is called, the createBackend () function will be called.

成员函数文档编制

[static] QSensorBackend *QSensorManager:: createBackend ( QSensor * sensor )

Create a backend for sensor . Returns null if no suitable backend exists.

[static] bool QSensorManager:: isBackendRegistered (const QByteArray & type , const QByteArray & identifier )

Returns true if the backend identified by type and identifier is registered.

This is a convenience method that helps out plugins doing dynamic registration.

[static] void QSensorManager:: registerBackend (const QByteArray & type , const QByteArray & identifier , QSensorBackendFactory * factory )

Register a sensor for type identifier must be unique.

factory will be asked to create instances of the backend.

[static] void QSensorManager:: setDefaultBackend (const QByteArray & type , const QByteArray & identifier )

Sets or overwrite the sensor type with the backend identifier .

[static] void QSensorManager:: unregisterBackend (const QByteArray & type , const QByteArray & identifier )

Unregister the backend for type with identifier .

Note that this only prevents new instance of the backend from being created. It does not invalidate the existing instances of the backend. The backend code should handle the disappearance of the underlying hardware itself.